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if condition throwing type mismatch error
#1
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Hi,

I am gettingtype mismatch errror when I run the following code's if condition. can some one tell me what is wrong in my code.
Attached error image.

And one more thing I have another attribute primary="true" which is optional and may not show up for all the image nodes also have to be in if condition. How to code that



Code:
Set urinode=xmlDoc.SelectSingleNode(imgcat)



                imgcategory= urinode.getAttribute("category")

                imgwidth=urinode.getAttribute("width")

                imgheight=urinode.getAttribute("height")



                nodepath1 = "/on/programs/program[" & i& "]/images/image[" & j & "]/URI/text()"

                Set node = xmlDoc.SelectSingleNode(nodepath1)



If ((imgcategory="Poster Art")&(imgwidth="72")&(imgheight="108")) then

                xlSheet.Rows(nRow).Columns(iCol).value=TMS

                xlSheet.Rows(nRow).Columns(iCol+1).value=node.NodeValue

                xlSheet.Rows(nRow).Columns(iCol+2).value=imgcategory

                xlSheet.Rows(nRow).Columns(iCol+3).value=Yes

else

                xlSheet.Rows(nRow).Columns(iCol).value=TMS

                xlSheet.Rows(nRow).Columns(iCol+1).value=node.NodeValue

                xlSheet.Rows(nRow).Columns(iCol+2).value=imgcategory

                End If


Attached Files
.doc   typemismatch.doc (Size: 31 KB / Downloads: 86)
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Messages In This Thread
if condition throwing type mismatch error - by rrdamuluri - 11-04-2010, 09:14 AM

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