Question about converting exponential values in DT

[cowboy49]

Hello,

I am trying to set a value that is represented by exponent 2^63. QTP always displays 9.22337203685478E+18. I want to display the actual number 9223372036854775808. Is there any way to do this? Will I have to create a function for this? If so, how can this be accomplished?

Thank you.

[inborntester]

Code:

a=Replace(FormatNumber(2^63,0,0,0),",","")
msgbox(a)

[cowboy49]

Thanks inborntester. But the number returned is rounded up the last digit
(9223372036854780000). I need the exact number 9223372036854775808.

[inborntester]

think, its native format conversion of VB compiler not able to optimise. Better you can develope you own Power function if its need is high. Logically it can ge possible with few for looks and array objects.

[Ankur]

Values in VBScript are accurate to 15 digits only. This should set you in the right direction (taken from http://www.windows-api.com/microsoft/VBS...stion.aspx )

Code:

Wscript.Echo AddInts(148991, 76561197960265728)

Function AddInts(lngValue1, lngValue2)
Dim V1Hi, V1Lo, V2Hi, V2Lo
Dim Temp1, Temp2, Carry, A1, A2, A3

V1Hi = Fix(lngValue1 / (10^10))
V1Lo = lngValue1 - (V1Hi * (10^10))

V2Hi = Fix(lngValue2 / (10^10))
V2Lo = lngValue2 - (V2Hi * (10^10))

Temp1 = V1Lo + V2Lo
Carry = Fix(Temp1 / (10^10))
A3 = Temp1 - (Carry * (10^10))
Temp2 = V1Hi + V2Hi + Carry
A1 = Fix(Temp2 / (10^10))
A2 = Temp2 - (A1 * (10^10))

AddInts = CStr(A1) & CStr(A2) & CStr(A3)

End Function

[cowboy49]

Thank you very much Ankur this worked for me!!